Flip a Coin 5 Times
Simulate 5 consecutive or simultaneous coin tosses. Analyze live Heads/Tails splits, longest streaks, and the full 32-outcome sample space.
Number of Coins:
HEADS:1(50.0%)
Deviation: 0.0%
TAILS:1(50.0%)
Complete Probability Distribution for 5 Coin Flips ($2^5 = 32$)
Calculated using P(X = k) = C(5, k) · (0.5)5:
| Heads Count (k) | Combinations C(5, k) | Exact Fraction | Percentage |
|---|---|---|---|
| 0 Heads (5 Tails) | 1 | 1 / 32 | 3.125% |
| 1 Head (4 Tails) | 5 | 5 / 32 | 15.625% |
| 2 Heads (3 Tails) | 10 | 10 / 32 | 31.250% |
| 3 Heads (2 Tails) | 10 | 10 / 32 | 31.250% |
| 4 Heads (1 Tail) | 5 | 5 / 32 | 15.625% |
| 5 Heads (0 Tails) | 1 | 1 / 32 | 3.125% |
Related Sequential & Multi-Coin Silos
Frequently Asked Questions
What are all the possible outcomes when flipping a coin 5 times?
There are 2^5 = 32 distinct permutations possible when tossing a coin 5 times (from HHHHH to TTTTT). Each specific sequence has an exact 1/32 (3.125%) theoretical probability.
What is the probability of getting exactly 3 heads in 5 flips?
Using the binomial formula C(5, 3) · (0.5)^5 = 10 / 32 = 31.250%. Getting either 3 Heads (31.25%) or 2 Heads (31.25%) are the two most common results, collectively occurring 62.5% of the time.
What is the probability of getting at least 4 heads in 5 flips?
Getting at least 4 heads means obtaining either 4 heads (5 combinations) or 5 heads (1 combination). Thus, P(X ≥ 4) = (5 + 1) / 32 = 6 / 32 = 18.750%.